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emmasim [6.3K]
3 years ago
13

I need this I really really do

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

but i cant see the question

Step-by-step explanation:

if not i would have helped

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How many solutions does this equation have? 6x-2=6x+7
Anon25 [30]

None, the equation 6x - 2 = 6x + 7 does not have any solutions.

<h3>What is an algebraic equation? </h3>

An algebraic equation is an equation that consists of numbers and variables. To solve the variables, there is a need to make use of some or all of the arithmetic operations such as:

  • Addition
  • Subtraction
  • Division, and
  • Multiplication

From the given equation:

6x - 2 = 6x + 7

Collect like terms

6x - 6x -2 - 7 = 0

0 - 9 = 0

Since there is no variable to solve for in the equation, we can conclude that the equation does not have any solutions.

Learn more about algebraic equations here:

brainly.com/question/4344214

6 0
3 years ago
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A book shelf is 3 1/2 feet long. if each book to be placed on the shelf is 2 1/4 inches wide,
Rudiy27

Answer: 18 books

Step-by-step explanation:

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3 years ago
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Suppose a is jointly proportional to b and c. if a=4 when b=8 and c = 9, then what is a when b=2 and c=18
asambeis [7]

From the given information, a exists jointly proportional to b and c.

then $$a \propto b c$

Therefore, the value of a exists 2.

<h3>What is the value of a?</h3>

Given, a exists jointly proportional to b and c.

$$a \propto b c$

Taking K as the constant of proportionality.

a = K b c

For b = 8 and c = 9, the value of a = 4

4 = K(8)(9)

4 = 72 K

Dividing the equation by 72, we get

$K=\frac{1}{18}

Using the value of K in the equation:

$a=\frac{b c}{18}

Substitute the values of b = 2 and c = 18, in the above equation

$a=\frac{2 \times 18}{18} \\

a = 2

Therefore, the value of a exists 2.

To learn more the value of x refers to:

brainly.com/question/11874663

#SPJ4

6 0
1 year ago
Brainliest to whoever gets this correct What was the equation of the graph below before it was shifted to the right 1.5 units?
mr Goodwill [35]
Hello I know this may be difficult on your end but you don’t always have to get the answer from someone you can contact a teacher and get help this keep be very helpful keep this in your head you are intelligent no matter what anyone tells you ask your teacher a question about the problem tell them you don’t get how to do it if you have to just whatever it takes for you to learn how to do it have a wonderful day or night bye!
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3 years ago
Anyone wanna join me and my friends on zo om? We’re all 13
poizon [28]
Pass the code I’ll join
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