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CaHeK987 [17]
2 years ago
9

2(8r+5)-3=4(4r-1)+11 is it an only solution or a no solution or infinite solution

Mathematics
1 answer:
pogonyaev2 years ago
3 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:

2(8r+5)-3=4(4r-1)+11  becomes  16r + 10 - 3 = 16r - 4 + 11.

Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7

This is always true, so we can conclude that this equation has infinitely many solutions.

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1. You are rolling a pair of dice. What's the probability of getting different numbers on both dice?
GaryK [48]

Answer:

  • 5/6

Step-by-step explanation:

<u>Total outcomes:</u>

  • 6*6 = 36

<u>Outcomes with same numbers on both dice:</u>

  • 6

<u>Outcomes with different numbers on both dice:</u>

  • 36 - 6 = 30

<u>Probability of different numbers on both dice:</u>

  • 30/36 = 5/6
7 0
3 years ago
Solve for a<br> -8 = a(2+5)^2 +41<br> A. -1<br> B. 1<br> C. -2<br> D. 2
mario62 [17]

Answer:A

Step-by-step explanation:

-8=a(2+5)^2 + 41

-8=a x 7^2 + 41

-8=a x 7 x 7 +41

-8=49a+41

Collect like terms

-8-41=49a

-49=49a

Divide both sides by 49

-49/49=49a/49

-1=a

a=-1

5 0
3 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
Graph the line with slope – 2 passing through the point (-5,5).
34kurt

Answer:

y = -2x - 5

Step-by-step explanation:

y = -2x + b

- To find the y-intercept, plug the values of the variables.

5 = -2(-5) + b

5 = 10 + b

- Subtract 10 from both sides.

-5 = b

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2 years ago
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