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Pavlova-9 [17]
3 years ago
5

Side AB of parallelogram ABCD has endpoints at (-1,6) and (6,9). What is the slope of the opposite side, CD?

Mathematics
1 answer:
Butoxors [25]3 years ago
8 0

Answer:

3/7

Step-by-step explanation:

Opposite sides on a parallelogram are parallel, and parallel lines have the same slope, so once we find the slope of AB, we'll know the slope of CD. Point A is (-1,6) and point B is (6,9), so the slope of AB (and by extension, CD) is

\dfrac{9-6}{6-(-1)}=\dfrac{3}{7}

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When a rectangular pyramid is cut at an angle the cross section is a triangle. True or false
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Answer:

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Step-by-step explanation:

Think about it. you are cutting a rectangle in half. and when you put it in dimensions its still the same thing!

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Step-by-step explanation:

You're Welcome :)

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A 250 mL beaker can hold 0.192 kg of acetone. What is the density of this substance, in g/mL? Round your answer to 3 significant
Andreyy89
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A teacher surveys 30 students on the the number of books they read over the summer.The data are represented in the box plot what
Margaret [11]

Answer:

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Step-by-step explanation:

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3 years ago
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
KATRIN_1 [288]

Answer: x^{\frac{2}{3} }

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

(x^{a})(x^{b}) = x^{a + b} <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

(x^{a})^{b} = x^{(a)(b)} <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

<em />

Let's apply it!

First, let's simplify what's inside the parenthesis.

x^{\frac{4}{3} } x^{\frac{2}{3} } <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

x^{\frac{4}{3} + \frac{2}{3} } = x^{\frac{6}{3} } = x^{2}

Now we have (x^{2})^{\frac{1}{3} }. Let's use the second rule.

(x^{2})^{\frac{1}{3} } = x^{\frac{2}{3} }

Hope this helps! :^)

7 0
3 years ago
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