Are you trying to solve the function operation? If so, your solution is 4 I believe. I don't really have a lot of info on this, but I hope this helps. If not, feel free to comment below and I'll see what I can do to help you further on this. Thanks and good luck!
First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
First of all, don't let "b" confuse you. Know that b = 5/6k = -10, so all you really have to solve for this problem is 
.
Before anything else, you have to isolate k. Do this my multiplying both sides by the reciprocal of 5/6.
The 6/5 and 5/6 cancel each other out, so we are left with 
--> 
---> 
So k = -12.
Hope this helped. Good luck.
