There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Since it is given that the reduction in the amount of waste each week is linear, it is conclusive that these data are also in arithmetic sequence. First, determine the common difference (d)
d = (a10 - a5) / (10 - 5)
Subsituting the known values,
d = (30 - 40) / 5 = -2
To determine any term (at) of the arithmetic sequence,
at = a1 + (n - 1) x d
Solve for a1 by using either the given a5 or a10,
40 = a1 + (5 -1) x -2 ; a1 = 48
The equation becomes,
at = 48 + -2(n -1)
Answer: -a-b?
Step-by-step explanation:
Answer:
x= 5/2, 1/3
Step-by-step explanation:
(2x – 5)(3x – 1) = 0
(2x – 5) = 5/2
(3x-1) = 1/3
really need brainliest!!
