Answer: A
Explanation:
It clearly shows your out
Answer: Result:Enter the number of quarters in the jar: 4
Enter the number of dimes in the jar: 5
Enter the number of nickels in the jar: 2
Enter the number of pennies in the jar: 5
Total value is 1 dollars and 65 cents
Explanation: import java.util.Scanner;public class Coins { public static void main(String[]args) { int quarters, dimes, nickels, pennies; int total;Scanner scan = new Scanner (System.in);System.out.print("Enter the number of quarters in the jar: "); quarters = scan.nextInt();System.out.print("Enter the number of dimes in the jar: ");dimes = scan.nextInt(); System.out.print("Enter the number of nickels in the jar: ");nickels= scan.nextInt(); System.out.print("Enter the number of pennies in the jar: ");pennies = scan.nextInt(); int total_cents = 25*quarters + dimes*10 + nickels*5 + pennies;total =total_cents/100;total_cents = total_cents %100;System.out.println("Total value is " + total + " dollars and " + total_cents + " cents ");}}
Result:Enter the number of quarters in the jar: 4
Enter the number of dimes in the jar: 5
Enter the number of nickels in the jar: 2
Enter the number of pennies in the jar: 5
Total value is 1 dollars and 65 cents
I think its the new age either that or end times
Answer:
The answer is "Technician B"
Explanation:
The OBDII is a standardized, automated framework which the USA EPA had approved and installed into its whole year of modeling (MY) 1996 and then into modern light-duty vehicles and trucks, recognized as "on-board diagnostics II."
- The DTC framework is a set of problematic diagnostic codes that used alert you if a vehicle is unable to operate using an on-board Diagnostic System.
- If the system of the automobile identifies a problem, a special DTC code is generated as well as a position sensor is sent to the instrument cluster, that's why Technician B is correct.
Answer:
Number of fragments is 3
Explanation:
The maximum size of data field in each fragment = 4468 - 20(IP Header)
= 4448 bytes
Hence, the number of required fragment = (10000 - 20)/4448
= 3
Fragment 1
Id = 218
offset = 0
total length = 4468 bytes
flag = 1
Fragment 2
Id = 218
offset = 556
total length = 4468 bytes
flag = 1
Fragment 3
Id = 218
offset = 1112
total length = 1144 bytes
flag = 0