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exis [7]
3 years ago
14

How would you write the following expression as a single term? 3[2ln(x - 1) - In(x)] + In(x + 1)

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

Lol i think this is da answer man

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3.8+(−2.9) I just need the sum please!
Lapatulllka [165]

Answer:

3.8 + (-2.9) is the same as 3.8 - 2.9. That equals .9 or 0.9

Step-by-step explanation:

DID I EXPLAIN NOWWWW

3 0
3 years ago
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When you run, your average step length is 42 inches. How many steps would you have to take to run 1 mile (5,280 feet)? Round to
LenaWriter [7]
To solve this, take the total distance (5,280) divide by the average step (42).
5,280/42 = 125.714
6 0
4 years ago
What is the HCF of 4 and 9? Please explain.​
kakasveta [241]
<h3>HCF of 4 and 9 is 1</h3>

  • HCF of 4 and 9 is the largest possible number that divides 4 and 9 exactly without any remainder. The factors of 4 and 9 are 1, 2, 4 and 1, 3, 9 respectively.

‌

So , the HCF of 4 and 9 is 1

8 0
2 years ago
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Find the 14" term<br> 7, 14, 28, 56,
Pavlova-9 [17]

Step-by-step explanation:

it seems we are dealing with multiplication, as the distances between the numbers get bigger and bigger.

and then I see

7 × 2 = 14

14 × 2 = 28

28 × 2 = 56

ok, so the sequence is created by always multiplying by 2.

a1 = 7

a2 = a1 × 2 = 7 × 2 = 14

a3 = a2 × 2 = a1 × 2 × 2 = 7 × 2 × 2 = 28

an = an-1 × 2 = a1 × 2^(n-1) = 7 × 2^(n-1)

a14 = 7 × 2¹³ = 7 × 8192 = 57,344

5 0
2 years ago
Which frame processing method causes a switch to wait until the first 64 bytes of the frame have been received before forwarding
malfutka [58]

Fragment free frame processing method causes a switch to wait until the first 64 bytes of the frame have been received before forwarding the frame to the destination device

  • Fragment free processing

An advanced type of cut-through switching is fragment-free (runtless switching). Before making a switching choice, switches engaged in cut-through switching merely read the Ethernet frame's destination MAC address field.

  • What distinguishes fragment-free switching from fast forward switching?

The latency in fast-forward mode is calculated between the first bit received and the first bit delivered. The most common cut-through switching technique is fast-forward switching. Switching without fragments: The switch stores the first 64 bytes of the frame in fragment-free switching before forwarding.

Learn more about frame here: brainly.com/question/19756844

#SPJ4

3 0
2 years ago
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