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3 years ago

14

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y sin(16x) = x cos(2y), (Ï

/2, Ï/4)

1 answer:

Mekhanik [1.2K]3 years ago

5 0

The answer you are seeking is c hope i helped have a nice day<span />

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Convert American $553 in Nepal rupees

hodyreva [135]

Answer:

65,994.52 Nepalese Rupee

Step-by-step explanation:

using conversion rate 1 usd = 119.74 nepalese rupee

553*119.74

7 0

3 years ago

(-6x+3)+(5x-4)<br><br> If you in the 7th grade or up you can answer this question

Otrada [13]

Answer:

-1x + -1

Step-by-step explanation:

(-6x+3)+(5x-4)

(-6x+3)+(5x-4)

-1x + -1

7 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

An aquarium is leaking water at the rate of three quarts in 4 days.How many quarts are leaked in 1 week?How many days does it ta

Simora [160]

Answer:

$\frac{21}{4}$ quarts

12 days

Step-by-step explanation:

Given that:

Amount of water leaked in 4 days = 3 quarts

To find:

Number of quarts leaked in 1 week?

Number of days taken for the leakage of 9 quarts of water?

Solution:

We can simply use unitary method or the ratio to find the answers of the questions asked in the statement.

As per question statement:

Amount of water leaked in 4 days = 3 quarts

Dividing by 4 on both sides:

Amount of water leaked in 1 day = $\frac{3}{4}$ quarts

Multiplying by 7 on both sides:

Amount of water leaked in 7 days = $\frac{3}{4}\times 7 = \frac{21}{4}$ quarts

Number of days taken for the leakage of 3 quarts = 4 days

Multiplying by 3 on both sides:

Number of days taken for the leakage of 3 $\times$ 3 = 9 quarts = 4 $\times$ 3 = <em>12 days</em>

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=2%20%2B%20y%20%3D%201" id="TexFormula1" title="2 + y = 1" alt="2 + y = 1" align="absmiddle" cl

zvonat [6]

Answer: y= -1

Step-by-step explanation:

2+y=1

y=1-2

y=-1

8 0

3 years ago

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