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3 years ago

What is the sum of 5+2 or 2+5? Why is the sum the same?

Mathematics

2 answers:

vitfil [10]3 years ago

5 0

Because of communicative properties, it won't matter what way you put it bevause it's still "2" and '5"

Vinvika [58]3 years ago

3 0

The sum is the same because 5 plus 2 equals 7 and 2 plus 5 equals 7 which the both have the same answer is just they switched the numbers

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The density of a certain material is such that it weighs 7 pounds for every 5.5 cups of volume. Express this density in kilogram

Sauron [17]

Answer:

$Density = 1.1546\ kg/pint$

Step-by-step explanation:

Given

$Mass = 7\ lb$

$Cups = 5.5$

Required

Determine the density in Kg/Pint

Density is calculated as thus:

$Density = \frac{Mass}{Volume}$

$Density = \frac{7\ lb}{5.5\ cups}$

Convert pound to kg

$Density = \frac{7/ 2.205\ kg}{5.5\ cups}$

$Density = \frac{3.17515\ kg}{5.5\ cups}$

Convert cups to pint

$Density = \frac{3.17515\ kg}{5.5/2\ pint}$

$Density = \frac{3.17515\ kg}{2.75\ pint}$

$Density = 1.1546\ kg/pint$

4 0

4 years ago

Can someone pl help me

Liula [17]

Answer:
Sure

Explanation:
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7 0

3 years ago

John guessed that he was going to get

leonid [27]

Answer:

he only got 93.333333333333% of what he thought he was going to get

Step-by-step explanation:

6 0

3 years ago

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the

dlinn [17]

We are to identify the three integers (let x, y and z be the three integers) given the conditions stated in the problem such as:
the sum of the three numbers is 92 => x+y+z = 92
the second number is three times the first number => y = 3x
the third number is ten less than twice the first number => 2x - 10 =z

Solving the equation, we have it:
x + y + z = 92
x + (3x) + (2x-10) =92
6x -10 = 92
6x = 92 +10
6x = 102
x = 17

solving for y:
y = 3x
y = 3*17
y = 51

solving for z, we have:
z = 2x -10
z = 2*17 - 10
z = 34 - 10
z = 24

The answers are:
x = 17
y = 51
z = 24

8 0

3 years ago

If 12 cats can catch 6 rats in 2 hours, how many hours would it take 50 cats to catch 75 rats?

sleet_krkn [62]

Answer:

50 cats would take 6 hours to catch 75 rats.

Step-by-step explanation:

After reading the statement we noticed the existence of two relationships:

1) <em>The amount of cats is directly proportional to the quantity of caught rats.</em>

2) <em>The amount of cats is inversely proportional to time taken to catch rats. </em>

That is to say:

$n \propto \frac{x}{y}$

$n = k\cdot \frac{x}{y}$ (Eq. 1)

Where:

$n$ - Amount of cats, dimensionless.

$x$ - Amount of caught rats, dimensionless.

$y$ - Time, measured in hours.

$k$ - Proportionality ratio, measured in hours.

Then, we obtain the following relationship by eliminating the proportionality ratio in (Eq. 1):

$\frac{n_{1}\cdot y_{1}}{x_{1}} = \frac{n_{2}\cdot y_{2}}{x_{2}}$ (Eq. 2)

Where:

$n_{1}$ , $n_{2}$ - Initial and final amounts of cats, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final amounts of caught rats, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final times, measured in hours.

Now we clear final time in (Eq. 2):

$y_{2} = y_{1}\cdot \left(\frac{n_{1}}{n_{2}} \right)\cdot \left(\frac{x_{2}}{x_{1}} \right)$

By knowing that $y_{1} = 2\,h$ , $n_{1} = 12$ , $x_{1} = 6$ , $n_{2} = 50$ , $x_{2} = 75$ , then we get that time taken by 50 cats to catch 75 rats is:

$y_{2} = (2\,h)\cdot \left(\frac{12}{50} \right)\cdot \left(\frac{75}{6}\right)$

$y_{2} = 6\,h$

50 cats would take 6 hours to catch 75 rats.

7 0

4 years ago