We are to identify the three integers (let x, y and z be the three integers) given the conditions stated in the problem such as: the sum of the three numbers is 92 => x+y+z = 92 the second number is three times the first number => y = 3x the third number is ten less than twice the first number => 2x - 10 =z
Solving the equation, we have it: x + y + z = 92 x + (3x) + (2x-10) =92 6x -10 = 92 6x = 92 +10 6x = 102 x = 17
solving for y: y = 3x y = 3*17 y = 51
solving for z, we have: z = 2x -10 z = 2*17 - 10 z = 34 - 10 z = 24
