Let, side of square = a
A.T.Q,
(a+4)(a-4) = a²-16 = 567-16= 551
She has 1 quarter, 1 dime and 13 nickels. So the probability that one coin at random is a nickel is 13/15.
My work:
1$= 100
1 quarter=25
1 dime=10
1+1+13= 15
25×1= 25
10×1= 10
5×13= 65
65+25+10= 100
The answer to this question is x=54
2x+2=3x-52
2x=3x-54
-x=-54
x=54
I hope this helps!!!!!