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elena-14-01-66 [18.8K]

3 years ago

15

If lim as x approaches 3 at f(x)/(2x-6)=f'(3)=0 which of the following must be true? I) (3,0) is a critical point of f(x). II) f

(x) has a local minimum at x=3 III) f(x) is continuous at x=3 a) I only b) II only c) III only d) I and III only e)I II and III

1 answer:

frosja888 [35]3 years ago

6 0

The answer is d.

F'(3)=0 so there is a critical point at x=3.

We don't know if the point at x=3 is a min or max since the original function is not given

In order for a function to be differentiable at a point it must also be continuous by definition.

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Please answer!it is grade 6 math

vova2212 [387]

Answer:

AB+BE+EF+GF+HG+AH = 14 #EQU 1
BC+CD+DE+EF+GF+BG = 22 #EQU 2
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IMPLEMENTING EQU 2 IN EQU 3
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2 years ago

If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

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This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

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3 years ago