<span> x − 2y = −1 => x = 2y -1
2x + y = −12
2(2y - 1) + y = -12
4y - 2 + y = -12
5y = -10
y = -2
x = 2</span>·(-2) - 1
x = -4 - 1
x = -5
Answer <span>D (-5,-2)</span>
The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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The equation is just 5 3/4 times 3 1/3. You make the denominators the same by multiplying them by each other. It will be 5 3/12 times 3 1/12. Now you times these two together. You can do this part yourself because it will be confusing on here. I hope i helped atleast a little.
So i'm assuming your eqtn is h = -16t^2 + 27t + 10
and we're looking for t = ? when h = 0
=> 16t^2 - 27t - 10 = 0
(16t + 5)(t - 2) = 0
t = 2 and t = -5/16
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