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3 years ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Line m has no y

-intercept, and its x-intercept is (3, 0). Line n has no x-intercept, and its y-intercept is (0, -4). The equation of line m is 3 , and the equation of line n is -4 .

1 answer:

Kobotan [32]3 years ago

7 0

Answer:

Part A) The equation of the line m is $x=3$

Part B) The equation of the line n is $y=-4$

Step-by-step explanation:

Part A) Line m has no y-intercept, and its x-intercept is (3, 0)

we know that

If a line has no y-intercept , then is a vertical line (parallel to the y-axis)

the equation of the line m is equal to the x-coordinate of the x-intercept

so

$x=3$

Part B) Line n has no x-intercept, and its y-intercept is (0, -4)

we know that

If a line has no x-intercept , then is a horizontal line (parallel to the x-axis)

the equation of the line n is equal to the y-coordinate of the y-intercept

so

$y=-4$

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This will be 3 + 5 + 4 each colour change = 12 each colour change. instead of doing the 56 each colour rotation below.

Step-by-step explanation:

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Top of tree will read in order so where ever you see capital R you will know its a new column for the tree and fill in when you understand the 254 transitions of a 5 column tree. Then change B + R accordingly when you get to row 6. Here you just start changing blue back to the top after row 5

Columns go down and rows go across its a new row you will need

approx 5-6 rows each colour change.

For the ones started for you below its just transition and colour stays where it is.

R x RT 45d RT (1,0) 45 RT (1,1) 45 RT (1,0)

R x R x

B x B x

B x B x

B x B x

'x' = RED Normal as you keep 0 zero central on all 4 bricks and work with top row as explained below.

Top RED brick you have to Right side place transition on every 2nd column for each colour and thenyou should find a pattern if youve numbered your papers or brcks to just see how it works. (hanging out one side call this 'off set' or call it T for transition (1.0)

RED Central 'diagonal' call it '45 degree rotate'

E ABCD RED Normal edge transition its edge so it hangs out

E ABCD RED On edge 45 degree diagonal its edge so it hangs out

2nd only change

S ABCD 1st red normal 2nd red Right side place rotate

S ABCD 1st red right side rotate 2nd red 45 degree rotate

S ABCD 1st red right side rotate 2nd central place 45 degree rotate

S ABCD 1st red right side rotate 2nd edge Normal edge transition

S ABCD 1st red right side rotate 2nd 45 degree its edge diagonal

2nd is repeated by changing 1st 4x more in bold. see what is now missing for 1st red. and copy the 2nd changes to 1st all whilst rotaing 2nd again in change .

Copy paste the work

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As the above shows 10 and when you finish 2nd and 1st it will be 14 total

Then 3 will be 14 again

and 4th brick will be 14 again

and 5th brick will be 14 again

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Then repeat again for 1 blue at the top change

Then repeat again for 2 blue at the top for change

Then repeat again for 2 blue in the top middle

Then repeat again for 2 blue in the bottom middle

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and colour code blue and red pens.

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and same for blue etc..

The end result will be 56 x 4 = 224 diagram tree

On ce you learn this it will take just 6 minutes to write out.

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