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e-lub [12.9K]
3 years ago
5

The graph shows the motion of two cars starting at different places on a highway. Their speeds can be compared by comparing the

steepness of the graphed lines.
Use the drop-down menus to complete the statements.
Car a travels (50,100,200,300) miles in 6 hours Car B travels (50,100,200,300) miles in 5 hours
Car A speed is (40,50,60,125,) miles per hour Car B speed is(40,50,60,125) miles per hour.
Car A traveled (faster than,slower than, the same speed) as Car B.
The graph for Car A is(steeper than,less steeperhan, or same steepness) as the graph for Car B

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Car a travels (300) miles in 6 hours

Car B travels (200) miles in 5 hours

Car A speed is (50) miles per hour

Car B speed is(40) miles per hour.

Car A traveled (faster than) Car B.

The graph for Car A is(steeper than) the graph for Car B

Step-by-step explanation:

distanc \:  = x - y

where x is starting location and y is the ending location

speed \:  =  \frac{distance}{time}

the rest we see once we have solve for distance and speed of the 2 cars

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3 0
2 years ago
Can someone help me solve this?
Wittaler [7]

Answer:

∠ ABC = 22°

Step-by-step explanation:

OA = OB ( radii of circle )

Then Δ OAB is isosceles with base angles congruent , that is

∠ OBA = ∠ OAB = 17x

The sum of the 3 angles in the triangle sum to 180°

17x + 17x + 11x = 180

45x = 180 ( divide both sides by 45 )

x = 4

Then

∠ OBA = 17x = 17(4) = 68°

BC is a tangent so ∠ OBC = 90°

∠ ABC = 90° - ∠ OBA = 90° - 68° = 22°

7 0
3 years ago
Find the distance between the points (-21, 17) and (33, 17)
Norma-Jean [14]
Plug it into the distance formula.

d= (sqrt) (x2-x1)^2 +(y2-y1)^2

d= (sqrt) (17-17)^2 + (33-(-21)^2
d=(sqrt) (0)^2 + (33 +21)^2
d= (sqrt) (54)^2
d= (sqrt) 2916
d=54

The distance is 54 units. 

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7 0
3 years ago
The equations of a system have the same slopes. What can you determine about the solution of the system of equations?
user100 [1]
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5 0
3 years ago
A parachute speed during a free fall reaches117 miles per hour What is the speed in feet per second At the speed how many feet w
qwelly [4]

Answer:

Speed is 171.6 ft/s and distance is 1716 feet

Step-by-step explanation:

Given that,

The speed of a parachute = 117 miles per hour.

1 mph = 1.47 ft/s

117 mph = 171.6 ft/s

We need to find the distance it travel during 10 s. We know that the distance covered is equal to the product of speed and time taken. So,

d = vt

d=171.6\ ft/s\times 10\ s\\\\=1716\ \text{feet}

Hence, this is the required solution.

3 0
3 years ago
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