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e-lub [12.9K]
3 years ago
5

The graph shows the motion of two cars starting at different places on a highway. Their speeds can be compared by comparing the

steepness of the graphed lines.
Use the drop-down menus to complete the statements.
Car a travels (50,100,200,300) miles in 6 hours Car B travels (50,100,200,300) miles in 5 hours
Car A speed is (40,50,60,125,) miles per hour Car B speed is(40,50,60,125) miles per hour.
Car A traveled (faster than,slower than, the same speed) as Car B.
The graph for Car A is(steeper than,less steeperhan, or same steepness) as the graph for Car B

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Car a travels (300) miles in 6 hours

Car B travels (200) miles in 5 hours

Car A speed is (50) miles per hour

Car B speed is(40) miles per hour.

Car A traveled (faster than) Car B.

The graph for Car A is(steeper than) the graph for Car B

Step-by-step explanation:

distanc \:  = x - y

where x is starting location and y is the ending location

speed \:  =  \frac{distance}{time}

the rest we see once we have solve for distance and speed of the 2 cars

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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Solve 2m + n = 2 and 3m - 2n = 3 using substitution.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

We can use the substitution method to solve linear equations of this form. Let's solve for m & n.

\left. \begin{array}  { l  }  { 2 m + n = 2 } \\ { 3 m - 2 n = 3 } \end{array} \right.

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2m+n=2, \: 3m-2n=3

Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.

2m+n=2

Subtract n from both sides of the equation.

2m=-n+2

Divide both sides by 2.

m=\frac{1}{2}\left(-n+2\right)  \\

Multiply 1/2 times -n+2.

m=-\frac{1}{2}n+1  \\

Substitute -\frac{n}{2}+1\\ for m in the other equation, 3m-2n=3.

3\left(-\frac{1}{2}n+1\right)-2n=3  \\

Multiply 3 times -\frac{n}{2}+1\\.

-\frac{3}{2}n+3-2n=3  \\

Add -\frac{3n}{2}\\ to -2n.

-\frac{7}{2}n+3=3  \\

Subtract 3 from both sides of the equation.

-\frac{7}{2}n=0  \\

Divide both sides of the equation by -\frac{7}{2}\\, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{\underline{ \bf \: n=0 }}

Substitute 0 for n in m=-\frac{1}{2}n+1\\. Because the resulting equation contains only one variable, you can solve for m directly.

\large \underline{ \underline{\bf \: m=1 }}

The system is now solved.

\huge \boxed{ \boxed{ \bf \: m=1, \: n=0 }}

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Step-by-step explanation:

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