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e-lub [12.9K]
3 years ago
5

The graph shows the motion of two cars starting at different places on a highway. Their speeds can be compared by comparing the

steepness of the graphed lines.
Use the drop-down menus to complete the statements.
Car a travels (50,100,200,300) miles in 6 hours Car B travels (50,100,200,300) miles in 5 hours
Car A speed is (40,50,60,125,) miles per hour Car B speed is(40,50,60,125) miles per hour.
Car A traveled (faster than,slower than, the same speed) as Car B.
The graph for Car A is(steeper than,less steeperhan, or same steepness) as the graph for Car B

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Car a travels (300) miles in 6 hours

Car B travels (200) miles in 5 hours

Car A speed is (50) miles per hour

Car B speed is(40) miles per hour.

Car A traveled (faster than) Car B.

The graph for Car A is(steeper than) the graph for Car B

Step-by-step explanation:

distanc \:  = x - y

where x is starting location and y is the ending location

speed \:  =  \frac{distance}{time}

the rest we see once we have solve for distance and speed of the 2 cars

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Please help with number 39
mr Goodwill [35]

You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation

... 3v + 7c = 4480

In intercept form, this equation is

... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480

Among other things, this tells us one solution is

... (v, c) = (0, 640)

The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.

The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)

We can also pick some number in between, say using 100 as the multiple

... (0 +100·7, 640 -100·3) = (700, 340)

In summary, your three solutions could be

... (visors, caps) = (0, 640), (700, 340), (1491, 1)

7 0
3 years ago
George has a small coin collection. He has collected 16 gold coins, 28 silver coins, 32 copper coins, and4 bronze coins. At a fl
erastovalidia [21]
16 +28+32+4=80 80 total coins x.15 =12 coins sold
3 0
3 years ago
0-9p one step equation​
tiny-mole [99]

Answer:

Step-by-step explanation:

0 - 9p = 0

9p = 0

p = 0

4 0
3 years ago
The data set is 7,8,10,11. How would the mean, median, and mode change if you added a 9 to the data set?
andrezito [222]
The mean would stay the same, the median would become 9, and the mode would stay the same.
3 0
3 years ago
These figures are similar. The perimeter and
jok3333 [9.3K]

Answer:

56.644 m^2

Step-by-step explanation:

It's a rule that if the ratio of the sides of 2 similar figures is a:b, the ratio of their areas is a^2:b^2. (I may not be using the standard variables or the exact wording here, but that's the basic idea.)

You can simplify this and understand it with squares. All squares are similar, right? Imagine a 2 in. by 2 in. square and a 4 in. by 4 in. square. The ratio of their sides is 2:4, or 1:2. (The ratio of their perimeters is the same thing. 2*4=8 inches for the smaller square, and 4*4=16 for the bigger square. 8:16=1:2) The ratio of their areas is 4:16, or 1:4. (1/2)^2=1/4

The same thing applies here. The perimeter of the larger figure divided by the perimeter of the smaller one is 34/20=1.7. That means that the area of the larger figure divided by the area of the smaller one is 1.7^2, or 2.89. You can write an equation where x is the area of the larger one:

x/19.6=2.89

x=56.644 m^2

Hope I could help you!

8 0
3 years ago
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