Please help im horrible at geometry
2 answers:
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Answer:
15 inches
Step-by-step explanation:
We assume that the edge of the small square is x (inches).
As the edge of the larger square is 2 inches greater than that of the smaller one, so that the edge of the larger square = edge of the small square + 2 = x + 2 (inches)
The equation to calculate the are of a square is: <em>Area = Edge^2 </em>
So that:
+) The area of the larger square is: <em>Area large square = </em><em> (square inches)</em>
+) The area of the smaller square is: <em>Area small square = </em><em>(square inches)</em>
<em />
As difference in area of both squares are 64 square inches, so that we have:
<em>Area large square - Area small square = 64 (square inches)</em>
<em>=> </em><em />
<em>=> </em><em />
<em>=> 4x + 4 = 64</em>
<em>=> 4x = 64 - 4 = 60 </em>
<em>=> x = 60/4 = 15 (inches)</em>
So the length of an edge of the smaller square is 15 inches
Answer:
a) () the n will be 5 the x will be (-32/243)^2.
b) written the same as a. except the c will replace the n and x will be (2y)^b.
c) the answer will be 0.4^3.
d) the answer would be (st)^v/u.
Hope this helps!
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