The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation, also called standard error $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 24, \sigma = 6.4, n = 64$

What are the mean and the standard error of the sample mean?

By the Central Limit Theorem, mean 24 and standard error $s = \frac{6.4}{\sqrt{64}} = 0.8$

7 0

2 years ago

Geometry! Please help!

Travka [436]

The answer is 315 as the formula is : a+b/2•h.

3 0

2 years ago

Read 2 more answers

A store is having a sale on used video game. Each game cost $12. Write an algebraic expression to represent the cost of buying v

alexandr1967 [171]

The algebraic expression you would write is 12v

8 0

2 years ago

Which is the sum of 3/10 and 1/3

Ilya [14]

Step-by-step explanation:

$\: \: \: \: \: \frac{3}{10} + \frac{1}{3} \\ \\ = \frac{3 \times 3}{10 \times 3} + \frac{1 \times 10}{3 \times 10} \\ \\ = \frac{9}{30} + \frac{10}{30} \\ \\ = \frac{19}{30} \\ \\ so \: as \: you \: see \: here \: we \: should \: put \: same \: denominator \\ \: for \: both \: fractions. \: hope \: this \: helps.. \\ good \: luck$

8 0

2 years ago