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2 years ago

If 1 and -1 are the zeroes of the polynomial p(x) = ax 3 + x 2 − 2x + b, find the values of a and b

Mathematics

1 answer:

vampirchik [111]2 years ago

6 0

Answer:

Step-by-step explanation:

p(x) = ax³ + x² - 2x + b

p(1) = a(1)³ + 1² - 2•1 + b = a + 1 - 2 + b = a + b - 1

a + b - 1 = 0 ⇒ b = 1 - a

p(-1) = a(-1)³ + (-1)² - 2(-1) + b = -a + 1 + 2 + b = - a + b + 3

- a + b + 3 = 0 ∧ b = 1 - a

- a + (1 - a) + 3 = 0

- a + 1 - a + 3 = 0

-2a + 4 = 0

-2a = -4

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A line includes the points (4, 8) and (3, 5). What is its equation in slope-intercept form? Write your answer using integers, pr

stich3 [128]

Answer:

A line includes the points (4, 8) and (3, 5) whose equation in slope-intercept form will be :

$y=3x-4$

Step-by-step explanation:

The point slope form: $(x_1,y_1) and(x_2,y_2)$

$(y-y_1)=m(x-x_1)$

where : m = Slope of the line

$m=\frac{y_2-y_1}{x_2-x_1}$

A line includes the points (4, 8) and (3, 5).The equation of the line will be:

$m=\frac{5-8}{3-4}=3$

$(y-8)=3\times (x-4)$

$y-8=3x-12$

$y=3x-4$

(y=mx+c), where c is intercept at y axis.

The above equation represents slope-intercept form of the line.

6 0

2 years ago

Write an equation of the line passing through the point A(2, 0) that is parallel to the line y = 3x−5

satela [25.4K]

Answer:

y = 3x-6

Step-by-step explanation:

y = 3x−5

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

m =3

Parallel lines have the same slope

We have the slope m=3 and a point (2,0)

y = mx+b

y = 3x+b

Substituting the point into the equation to solve for b

0 = 3(2)+b

0 = 6+b

b = -6

y = 3x-6

4 0

2 years ago

Read 2 more answers

Distribute -(-4v+6.3w-9.8)

Firdavs [7]

Answer:

4v-6.3w+9.8

Step-by-step explanation:

If you distribute the negative sign (same as distributing -1), then you get -(-4v) + (-6.3w) - (-(9.8))

Basically it's switching the signs

Hope that helped :)

3 0

2 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

1 year ago

PLEASE, PLEASE, PLEASE I NEED HELP IT TEN POINT AND WILL BE MARK AS BRAINLIST! ttttttthhhhhhhaaaaaannnnnnkkkk

kow [346]

Answer: B.1/6 quarts

Step-by-step explanation:

3/4 Minutes = 1/8 Juice

4/3 * 3/4 Minutes * 4/3 * 1/8 Juice

1 Minutes = 1/6 quarts

Making B your answer

6 0

2 years ago