If 1 and -1 are the zeroes of the polynomial p(x) = ax 3 + x 2 − 2x + b, find the values of a and b

Mathematics

1 answer:

vampirchik [111]2 years ago

6 0

Answer:

Step-by-step explanation:

p(x) = ax³ + x² - 2x + b

p(1) = a(1)³ + 1² - 2•1 + b = a + 1 - 2 + b = a + b - 1

a + b - 1 = 0 ⇒ b = 1 - a

p(-1) = a(-1)³ + (-1)² - 2(-1) + b = -a + 1 + 2 + b = - a + b + 3

- a + b + 3 = 0 ∧ b = 1 - a

- a + (1 - a) + 3 = 0

- a + 1 - a + 3 = 0

-2a + 4 = 0

-2a = -4

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Which ordered pairs make both inequalities true? Check all that apply.

Andrej [43]

We can actually deduce here that the ordered pairs that make both inequalities true are:

(1,1)
(2, 2)

<h3>What is inequality?</h3>

An inequality is known to be an expression that shows that certain variables or values are not equal to each other. It is usually seen in an inequality expression as:

> (greater than)
< (less than)
≥ (greater than or equal to)
≤ (less than or equal to).

We see the attached image that shows the graph of inequality and which completes the question.

The options that complete the question are:

A. –2, 2

B. (0, 0)

C. (1,1)

D. (1, 3)

E. (2, 2)

When we insert the values of each axes into the inequality expressions given, we will discover that the ordered pairs that the inequalities true is (1,1) and (2, 2).

Learn more about inequality on brainly.com/question/25275758

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