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Mariulka [41]
3 years ago
12

What're all the numbers divisible by 3 and 9?

Mathematics
2 answers:
KIM [24]3 years ago
7 0
3 and 1 are divisible by 3. 3, 1, and 9 are divisible by 9
Ierofanga [76]3 years ago
7 0
Now if you're talking about your last question, you're still using this. https://us-static.z-dn.net/files/d93/1c39d6bfe22a33d556dc29ee364f6219.png

So, 27, 72, 45, 81, and 54 are divisible by 3 and 9.


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the soccer field at Mario's school has an area of 6,000 square meters. how can mario show the area as a whole number multiplied
ruslelena [56]

6,000 = 6 x 10^3 square meters.
6,000 = 60 x 10^2 square meters
6,000 = 600 x 10^1 square meters.
You can pick which you wish to report in.
Hope this helps :-)
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What transformation is described by the
spayn [35]

Answer:

Step-by-step explanation:

Any alteration to the x value means that the function will move right. There are no exceptions to this that  I can think of.

8 0
2 years ago
What are the solutions to the equation
frosja888 [35]

Answer:

C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions ax^2+bx+c=0 with a\neq 0 the Bhaskara's Formula is:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}

It usually has two solutions.

Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

Observation: \sqrt{-1}=i

x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

And,

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

3 0
3 years ago
When you multiple 2/3 by a fraction less than one, how does the product compare to the fraction?Explain
pentagon [3]
Thanks for the question!

It will be less than the fraction.

Hope this helps!
7 0
3 years ago
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