Following the table and knowing that the total number of students interviewed were 158 ( we can see this by looking adding either the total number of upperclassment or adding the total number of people with jobs or no jobs, this value is at the bottom right of the table in the figure attached).
Recall that:

In the figure provided each of these terms is highlighted in a different color. To convert these values to their matching probabilities we have to divide each by the total number of students, this is due to the fact that the probability is the number of favorable cases (in this case a group matching the qualities we seek) divided by the total amount of cases ( that is the total number of people interviewed). In the figure the answer is provided. For the intersection of the two events we're looking for people that is both an undercalssman and also has a job.
Answer:
The solution is (0, 4)
Step-by-step explanation:
Please pay attention to the first two equations and drop the last two:
12x−5y=−20 y=x+4 x=x=x, equals y=y=y should ideally be:
12x−5y=−20
y=x+4
Let's find x. Substitute x + 4 for y in the first equation, obtaining:
12x - 5(x + 4) = -20
Carrying out the indicated multiplication, we get:
12x - 5x - 20 = -20, or 7x = 0
If x = 0 then y must be 0 + 4, or 4.
The solution is (0, 4)
X= -15
First, we want to combine like terms.
4x-10=20+6x
Subtract 4x from both sides
-10=20+2x
Subtract 20 from both sides
-30=2x
Divide by 2 to isolate the variable
X= -15
-1/3 . -3/1 = 1
......................
2/3j-2/9
=2/3j-2/3*1/3
=2/3(j-1/3)