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Vitek1552 [10]
3 years ago
14

Robert is going on a 2-day canoeing trip with his outdoor adventure group. Robert paddled at a constant sped and travels 3/4 of

a mile in 15 minutes.
a. Create a table to determine how long it takes Robert to canoe 1 mile.
b. On the first day of the trip, Robert canoes for 3 hours. How far did Robert travel?
c. On the second day of the trip, Robert travels 6 miles down the river. How many hours did he send paddling?
d. Another member of the group, Matthew, can canoe 3/2 miles in 45 minutes. Who is traveling at a faster rate, Robert or Matthew? Explain your reasoning. (NO LINKS)
Mathematics
1 answer:
siniylev [52]3 years ago
5 0

Answer:

i think the Answer is D

Step-by-step explanation:

There are really questions  to answer .

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2862279

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Simplify the trigonometric expression.

Call the expression E:

\mathsf{E=\dfrac{sin\,\theta}{\sqrt{1-sin^2\,\theta}}\qquad\qquad(but~~1-sin^2\,\theta=cos^2\,\theta)}\\\\\\
\mathsf{E=\dfrac{sin\,\theta}{\sqrt{cos^2\,\theta}}}\\\\\\
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\mathsf{E}=\left\{\!\begin{array}{rl}\mathsf{\dfrac{sin\,\theta}{cos\,\theta}\,,}&\mathsf{\quad if~~cos\,\theta>0}\\\\\mathsf{\dfrac{sin\,\theta}{-\,cos\,\theta}\,,}&\mathsf{\quad if~~cos\,\theta


So basically E is equivalent to \pm\,\mathsf{tan\,\theta}, where the sign depends on which quadrant \theta lies. Shortly,

\mathsf{\dfrac{sin\,\theta}{\sqrt{1-sin^2\,\theta}}}=\left\{\!
\begin{array}{rl}
\mathsf{tan\,\theta,}&\mathsf{\quad if~\theta~lies~either~in~the~1^{st}~or~the~4^{th}~quadrant}\\\\
\mathsf{-\,tan\,\theta,}&\mathsf{\quad if~\theta~lies~either~in~the~2^{nd}~or~the~3^{rd}~quadrant}
\end{array}


I hope this helps. =)


Tags:  <em>simplify trigonometric trig expression sine cosine tangent sin cos tan absolute value modulus trigonometry</em>

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