Answer:
The answer is B!
Step-by-step explanation:
Answer:
The answer to your question is letter C. 7y³ + 7n²y² - 22y²
Step-by-step explanation:
y²(4y + 7n² + 2) - 3y² (-y + 8)
Multiply
4y³ + 7n²y² + 2y² + 3y³ - 24y²
Use the associative property for like terms
(4y³ + 3y³) + (2y² - 24y²) + 7n²y²
Simplify like terms
7y³ - 22y² + 7n²y² or 7y³ + 7n²y² - 22y²
Answer:
-77, -78, -79
Step-by-step explanation:
let one of the integers be x
since the integers are consecutive, the other 2 integers must be
(x+1) and (x+2)
given that sum of the integers is -234,
x + (x+1) + (x+2) = -234
x + x + 1 + x + 2 = -234
3x + 3 = -234 (subtract 3 from both sides)
3x = -234-3
3x = -237 (divide both sides by 3)
x = -237 / 3
x = -79 (answer)
hence the other two numbers are
(x + 1) = -79 + 1 = -78 (answer)
and
(x+2) = -79 + 2 = -77 (answer)
Answer:
13a+12. ( if you dont have to find a)
Step-by-step explanation:
It depends if you have to find the value of a. If not, then Im going to say 13a + 12
Answer:
Now we can calculate the p value with this probability:
If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.
Step-by-step explanation:
Information given
n=78 represent the random sample taken
X=36 represent the students with jobs
estimated proportion of students with jobs
is the value that we want to test
z would represent the statistic
represent the p value
Hypothesis to test
We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info we got:
Now we can calculate the p value with this probability:
If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.