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Illusion [34]
3 years ago
7

Two objects were lifted by a machine. One object had a mass of 2 kilograms and was lifted at a speed of 2m/sec. the other had a

mass of 4 kilograms and was lifted at a rate of 3m/sec.
Mathematics
1 answer:
OLga [1]3 years ago
4 0
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
     potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
     potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.

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Sergeeva-Olga [200]

Answer:

C

Step-by-step explanation:

Round the decimals.

5 0
3 years ago
How do I solve the equation 6=-w/8
MrRa [10]

Answer:

-48

Step-by-step explanation:

Multiply both sides of the equation by -8

-8(6)  = \frac{-w}{8}(-8)

-48 = w

4 0
2 years ago
Read 2 more answers
Which point is a solution to the inequality?
Aliun [14]
You haven’t provided any equations so it’s not possible to solve this question
5 0
3 years ago
Look at each expression below. Indicate if each is equivalent to 64g – 40h. Select Yes or No for each expression.
Assoli18 [71]

Answer:

B

Hope this helps

Step-by-step explanation:

4 0
3 years ago
(Please show your work) (1 kwh = 3400 BTU’s 1 gallon = 8 pounds of water) The water coming into a dishwasher from a water heater
shtirl [24]

Answer:

5700 BTU

Step-by-step explanation:

Data provided in the question:

1 kwh = 3400 BTU’s

1 gallon = 8 pounds of water

Initial temperature = 50°F

Final temperature = 100°F

Water used by dishwasher = 10 gallons

Electrical energy used = 0.5 kwh

Now,

Water used in pounds = 10 × 8 = 80 lb

Total electrical energy used in BTU = 0.5 × 3400 BTU     [ as 1 kwh = 3400 BTU]

Total electrical energy used in BTU = 1700 BTU

Energy used by water = Water used by dishwasher × Change in temperature × Specific heat of water

[  Specific heat of water = 1 BTU / °F.lb ]

Thus,

Energy used by water = 80 × 1 × ( 100 - 50 )

= 4000 BTU

Hence,

Total energy used = 1700 BTU + 4000 BTU = 5700 BTU

8 0
3 years ago
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