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Mazyrski [523]
2 years ago
5

The surface area of this rectangular prism is 34 square centimeters. What is the volume is the width is 1 cm, the length is 2 cm

, and the height is x?
Mathematics
1 answer:
Bezzdna [24]2 years ago
8 0

Answer: 10\ cm^3

Step-by-step explanation:

Given

The surface area of a rectangular prism is 34\ cm^2

Width of prism w=1\ cm

Length of prism l=2\ cm

height of prism h=x\ cm

Surface area is given by

S.A.=2[lw+wh+hl]

Put values

34=2[2\times 1+1\times x+2x]\\17=2+3x\\15=3x\\x=5\ cm

Now, the volume of Prism is given by

V=l\times w\times h

\Rightarrow V=2\times1\times 5=10\ cm^3

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M + 5 = 5<br> + 5 can you guys help
sattari [20]

Answer:

the answer would be 0 because 0+5=5

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3 years ago
Find the slopes of the liner functions
LuckyWell [14K]

Answer:

The slope of the line given by the linear equation is -2

The slope of the line shown in the graph is -1

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

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  • b is the y-intercept

The rule of the slope of a line is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are two points lie on the line

Let us use these rules to answer the question

∵ The linear equation is y = -2x + 7

→ By comparing it with the form of the linear equation above

∴ m = -2

∵ m is the slope of the line represented by the given equation

∴ The slope of the line given by the linear equation is -2

From the given figure

∵ The line passes through points (6, 0) and (0, 6)

∴ x1 = 6 and y1 = 0

∴ x2 = 0 and y2 = 6

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{6-0}{0-6}=\frac{6}{-6}

∴ m = -1

∵ m is the slope of the line shown in the graph

∴ The slope of the line shown in the graph is -1

6 0
2 years ago
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Ill need more detail

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Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and sample size. mu e
Mademuasel [1]

Answer:

\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

Solution to the problem

Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =86,\sigma =24)  

We select a sample of size n=64. That represent the sample size.  

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:  

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The mean for the sample distirbution would be given by:

\mu_{\bar x}=86

And the deviation given by:

\sigma_{\bar x} =\frac{24}{\sqrt{64}}=3

And then the distribution for the sample mean is:

\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)

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