All categories

3 years ago

Find the first four terms of the sequence an = 4n-6

Mathematics

1 answer:

natulia [17]3 years ago

5 0

Answer:

The first four terms of the sequence are-6, -2, 2 and 6

Step-by-step explanation:

The given sequence is $a_n=4n-6$

In order to find the first four term of the sequence we put n =0, 1, 2 and 3.

For n =0

$a_0=4(0)-6=-6$

For n =1

$a_1=4(1)-6=-2$

For n =2

$a_2=4(2)-6=2$

For n =3

$a_3=4(3)-6=6$

Therefore, the first four terms of the sequence are

-6, -2, 2 and 6

You might be interested in

What is the distance between the points (4,5) and (10,13) on a coordinate plane?

Readme [11.4K]

The distacne between the points (x1,y1) and (x2,y2) is
$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so

$D=\sqrt{(10-4)^2+(13-5)^2}$
$D=\sqrt{(6)^2+(8)^2}$
$D=\sqrt{36+64}$
D=√100
D=10
the distance is 10 units

7 0

2 years ago

Help?????? Im very confused (in attachment )

Vikki [24]

4. Option 3, a has length of infinity and mn does not split a, a splits mn
5. Option 2, only 1 possibility, since it has to split mn into equal parts

8 0

2 years ago

Also this question tooo pleease, PS: what topic is this <br> Solve for x.

MrRissso [65]

This falls under geometry. The two labeled angles are congruent, which means the line segment between them (AD in the image) is a bisector of the angle at vertex A. Use the angle bisector theorem, which says that

$\dfrac{BD}{DC}=\dfrac{AB}{AC}\iff\dfrac{12}{(5+9x)-12}=\dfrac{15}{25}$

$\dfrac{12}{9x-7}=\dfrac35$

$20=9x-7$

$x=3$

8 0

2 years ago

An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different ti

Simora [160]

Answer:

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 ....... Equation 1

95 E + 110W = 400 ......Equation 2

Hence,

An Eastbound train has been travelling for = (E) = 2.67 hours

A Westbound train has been travelling for = (W) = 1.33 hours

Step-by-step explanation:

An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different times. After 4 hours, they are 4 00 miles apart. Which system of linear equations can be used to determine the time that each of the trains has been traveling?

Speed = Distance/Time

Distance = Speed × Time

Let the time

An Eastbound train = (E)

A Westbound train = (W)

E + W = 4 hours ....... Equation 1

95mph × E + 110mph × W = 400 miles

95 E + 110W = 400 miles ......Equation 2

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 ....... Equation 1

95 E + 110W = 400 ......Equation 2

E = 4 - W

We substitute 4 - W for E in Equation 2

95 (4 - W) + 110W = 400

380 - 95W + 110W = 400

Collect like terms

95W - 110W = 400 - 380

15W = 20

W = 20/15

W = 1.3333333333 hours

≈ 1.33 hours

E = 4 - W

E = 4 - 1.33 hours

E = 2.67 hours

Therefore,

An Eastbound train has been travelling for = (E) = 2.67 hours

A Westbound train has been travelling for = (W) = 1.33 hours

8 0

3 years ago

Please answer this question fast in two minutes

almond37 [142]

Answer:

∠CGA or ∠DGF

Step-by-step explanation:

Supplementary angles add up 180°

∠CGD + ∠CGA = 180°

∠CGD + ∠DGF = 180°

8 0

2 years ago