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3 years ago

Find the first four terms of the sequence an = 4n-6

Mathematics

1 answer:

natulia [17]3 years ago

5 0

Answer:

The first four terms of the sequence are-6, -2, 2 and 6

Step-by-step explanation:

The given sequence is $a_n=4n-6$

In order to find the first four term of the sequence we put n =0, 1, 2 and 3.

For n =0

$a_0=4(0)-6=-6$

For n =1

$a_1=4(1)-6=-2$

For n =2

$a_2=4(2)-6=2$

For n =3

$a_3=4(3)-6=6$

Therefore, the first four terms of the sequence are

-6, -2, 2 and 6

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In a bolt manufacturing factory, machines 4, Band C produce 25%, 30% and 45% of

Ugo [173]

In the first 25% of the produce, 7% of that is defective. Which means that 25%*93% is not defective.

=20.75% not defective.

In the second 30% of the produce, 6% is defective Which means that 30%*94%

=28.2% not defective

Now for the 3rd 45% of the produce, 4% is defective which means that

45%*96%

=43.2% not defective.

Added together, 20.75+28.2+43.2=92.15% not defective.

7 0

2 years ago

Please help! Thank you so much.

inysia [295]

Answer:

4 over 5

Step-by-step explanation:

its 4 over 5 because your going to get a decimal and the other answers you will get a integer which the question isnt asking for so the answer is 4 over 5

4 0

3 years ago

What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)

nordsb [41]

Y = A cos(Bx + C)
A - amplitude
$\frac{2\pi}{B}$ - period
$- \frac{C}{B}$ - phase shift

$y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}
\\
\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}
\\
\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}$

Amplitude: 5
Period: $\frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi$
Phase shift: $- \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}$

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3 years ago

How do properties of integer exponents help you write equivalent expressions

olga55 [171]

When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.

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3 years ago

every plz go report that page I keep seeing that same question every time I refresh what there posting is not funny they should

steposvetlana [31]

Answer:

what is it?

Step-by-step explanation:

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2 years ago