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Damm [24]
3 years ago
15

What is the inequality of a number n minus 3 is at least -5

Mathematics
1 answer:
Dimas [21]3 years ago
3 0

Answer: n-3\geq -5

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The elevation of the harbor is ____ than the elevation at sea level.
antoniya [11.8K]

Answer: less

Step-by-step explanation:

if when you say harbor you’re referring to were ships are docked im pretty it doesn’t get as elevated as the sea

7 0
3 years ago
The midpoint of RS¯¯¯¯¯¯¯ is M. Use the given endpoint R(23, 14) and midpoint M(13, 8) to find the coordinates of the other endp
Oksanka [162]

The coordinates of other endpoint S is (3, 2)

<h3><u>Solution:</u></h3>

Given that midpoint of RS is M

Given endpoint R(23, 14) and midpoint M(13, 8)

To find: coordinates of the other endpoint S

<em><u>The formula for midpoint is given as:</u></em>

For a line containing containing two points (x_1, y_1) and (x_2, y_2) midpoint is given as:

m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here in this problem,

m(x, y) = (13, 8)

(x_1, y_1) = (23, 14)\\\\(x_2, y_2) = ?

Substituting the given values in above formula, we get

(13,8)=\left(\frac{23+x_{2}}{2}, \frac{14+y_{2}}{2}\right)

Comparing both the sides we get,

\begin{aligned}&13=\frac{23+x_{2}}{2} \text { and } 8=\frac{14+y_{2}}{2}\\\\&26=23+x_{2} \text { and } 16=14+y_{2}\\\\&x_{2}=3 \text { and } y_{2}=2\end{aligned}

Thus the coordinates of other endpoint S is (3, 2)

8 0
3 years ago
What is the answer to this question <br> 2x - 6x
Angelina_Jolie [31]

Answer:

-4x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write an equation for the ordered pairs (0,5) (1,0)
Phoenix [80]
M=0-5/1-0
m=-5/1=-5
y-y1=m*(x-x1)
y-5=-5(x-0)
y-5=-5x
y=-5x+5
7 0
3 years ago
What is the product?
Sophie [7]

Answer:

Step-by-step explanation:

In exponent multiplication, if base are same just add the powers.

(-6a^{3}b+2ab^{2})(5a^{2}-2ab^{2}-b)=(-6a^{3}b)*(5a^{2}-2ab^{2}-b)+2ab^{2}*(5a^{2}-2ab^{2}-b)\\\\

                                             =(-6a^{3}b)*5a^{2}-(-6a^{3}b)*2ab^{2}-(-6a^{3}b)*b+ 2ab^{2}*5a^{2}-2ab^{2}*2ab^{2}-2ab^{2}*b\\\\=-30a^{3+2}b+12a^{3+1}b^{1+2}+6a^{3}b^{1+1}+10a^{1+2}b^{2}-4a^{1+1}b^{2+2}-2ab^{2+1}\\\\=-30a^{5}b+12a^{4}b^{3}+6a^{3}b^{2}+10a^{3}b^{2}-4a^{2}b^{4}-2ab^{3}\\

6 0
3 years ago
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