K₂CrO₄(aq) + Ba(NO₃)₂(aq) = BaCrO₄(s) + 2KNO₃(aq)
2K⁺ + CrO₄²⁻ + Ba²⁺ + 2NO₃⁻ = BaCrO₄ + 2K⁺ + 2NO₃⁻
spectator ions: K⁺, NO₃⁻
We are asked to solve the temperature do Potassium Nitrate KNO3 and Sodium Chloride NaCl has the same molar solubility. The answer is 44.5 degrees Celsius. As per the definition of solubility temperature, the solubility increases when the temperature increases where molecules are allowed to move faster at a higher temperature.
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Both containers have the same number of molecules= 5.62 x 10²³
<h3>Further explanation</h3>
Given
22.4 L of hydrogen gas
22.4 L of oxygen gas
25°C and 1 atm.
Required
true statement
Solution
Conditions at T 25 ° C and P 1 atm are stated by RTP (Room Temperature and Pressure). Vm in this condition = 24 liters / mol
and from Avogadro's Law :
<em>At the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles </em>
So two gas have the same molecules
1 mol = 6.02 x 10²³ molecules
24 L = 1 mol, so for 22.4 L :
