Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150 0.0394
0.250 0.109
0.350 0.214
0.500 0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
The first step in the scientific methods is ask a question
The relation between force, mass of an object and its acceleration is given by following equation
F = mass of object X acceleration
The unit of Force is Newton (N)
unit of acceleration is ms⁻²
unit of mass if Kg
[all these are SI units]
Mass of object =
mass of sprinter =