Question

A .115 L sample of dry air has a pressure of 1.0895633 atm at 377 K. What is the volume of the sample if the temperature is increased to 483 K when the pressure is kept constant?

Answer 1

Answer:

V= 0.147 L

Explanation:

This is simply the application of combined gas law twice, to find the unknowns.

Combined gas law states that: $PV = nRT$

P= pressure of air

V= volume of air

n= moles of air

R= Universal gas constant ( 0.08205 L atm mol⁻¹ K⁻¹)

T= Absolute temperature in kelvin.

$n=\frac{P * 0.115}{R * 377}$

Now, applying the same gas law at 483K and substituting for n

$V = \frac{P * 0.115}{R * 377} * \frac{R* 483}{P}$

V= $\frac{0.115 * 483}{377}$

V= 0.147 L