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VladimirAG [237]
3 years ago
11

who tryna do this https://app.senecalearning.com/classroom/course/ce229c78-825a-4e3f-a348-e79401f6a225/section/d2802d1d-741a-43f

b-92fd-52b298819b6c/session
Chemistry
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:ME

Explanation:

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If you did not use a watch glass to cover your stock iodine solution, and the concentration of iodine decreased over the course
anygoal [31]

Answer::

<u><em>Lower rate of reaction</em></u>

Explanation:

Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.

This however may not be the case if the iodine in question is  catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.

I hope this explanation fits the brief.

5 0
3 years ago
Why is there a threshold in response to some toxins?
Vedmedyk [2.9K]
Everything is deadly at a certain amount. Sometimes you accidently incest a small amount of something that's toxic, but it doesn't really do any harm because of how little it is. The body just gets rid of it during the its normal biological processes.

There's a certain amount of the toxin that you have to reach before the body begins to really feel it's effects and begin to get rid of it (vomiting, clamminess, all that jazz).

Of course it depends on the substance in question, some things are way more dangerous in much less amounts than others (e.g. ricin vs. poinsettia flowers).

Hope this helps!
5 0
3 years ago
Science / Chemistry Worksheet
kaheart [24]

Explanation:

K2O Now the cation is the element at the front so it would be K2 because the 2 belongs with the K which is Potassium and now Anion is the last element O for oxygen

7 0
3 years ago
Balanced Chemical Equation: 2H2(g)+O2(g)——&gt; 2H2O(g)
Tcecarenko [31]

You must use 134 g O₂ to produce 118 g H₂O.

\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \%

\text{Theoretical yield} = \text{Actual yield}\times \frac{100\%}{\%\text{ yield}} = \text{118 g }\times \frac{100 \%}{78.2 \%} = \text{150.9 g}

M_r:          32.00    18.02  

         2H₂ + O₂ ⟶ 2H₂O

Moles of H₂O = 150.9 g H₂O × (1 mol H₂O/18.02 g H₂O) = 8.374 mol H₂O

Moles of O₂ = 8.374 mol H₂O × (1 mol O₂/2 mol H₂O) = 4.187 mol O₂

Mass of O₂ = 4.1877 mol O₂ × (32.00 g O₂/1 mol O₂) = 134 g O₂

6 0
3 years ago
Going against the natural flow of heat and moving thermal energy from a low temperature to a high temperature is _____.
BARSIC [14]

Answer: The correct answer is "refrigeration".

Explanation:

Refrigeration is the process of rejecting heat from low temperature reservoir and transfers it to high temperature reservoir. Here, the heat is taken from the colder body and reject it to hotter body. The sink is at the lower temperature. The source is at the higher temperature.

In heat engine, the heat is transferred from high temperature reservoir to the low temperature reservoir. It is just opposite of the refrigeration.

Therefore, going against the natural flow of heat and moving thermal energy from a low temperature to a high temperature is refrigeration.

7 0
3 years ago
Read 2 more answers
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