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maria [59]
3 years ago
14

How are real numbers used to describe a real-world situations

Mathematics
1 answer:
avanturin [10]3 years ago
3 0
Real numbers are all rational numbers such as -7 and 4/3 and all irrational numbers. Real numbers are mainly used in counting and also in measurement which is used a lot in real world situations. These numbers help is quantify in the real world.
Hope this helps! Can you give me a brainliest please? I need them badly !
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What is the perimeter of a trapezoid?Units
Elan Coil [88]
20 units





Perimeter =add up all sides.




Perimeter = 5+1+5+9

=20 units
5 0
3 years ago
Please answer this I don't understand how to do it thanks
Mars2501 [29]

Answer:

The answer is 8.6×10¹⁴

Step-by-step explanation:

You can evaluate it :

(4.3 \times  {10}^{8} ) \times (2.0 \times  {10}^{6} )

= (4.3 \times 2.0) \times ( {10}^{8}  \times  {10}^{6} )

= 8.6 \times  {10}^{8 + 6}

=8.6 \times  {10}^{14}

6 0
3 years ago
Read 2 more answers
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
A 12 ft ladder is leaning against a building. The ladder makes a 45 degree angle with the building how far up is the building do
Ghella [55]

Answer:

The ladder reach a height 8.485 ft.

Step-by-step explanation:

The ladder with the building made right angle triangle

The length of the ladder is the hypotenuse 12 ft.

The angle between the ladder and the building is 45°

The height of the ladder reach is the vertical side of the Δ

∴ h = 12 cos 45° = 6√2 = 8.485 ft.

4 0
3 years ago
I need help solving these problems please.
ddd [48]

5. 15 x 3/4 = 11.25

6. 10 x 1/2 = 5

7.  11 x 2 = 22

8. 12/1.5 = 8

5 0
3 years ago
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