Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
<h3>
Answer: 49</h3>
Work Shown:
Replace x with 3, replace y with -8. Use order of operations PEMDAS to simplify.
x^2 + y^2 + x*y
3^2 + (-8)^2 + 3*(-8)
9 + 64 - 24
73 - 24
49
The correct answer is B.
With negative numbers, the "smaller" the number looks the bigger it is.
-2 is greater than -4.
Positive numbers are greater than negative numbers so we have:
8 > -2 > -4
THE ANSWER IS 4pi
The volume of a sphere is calculated using the formula 4pi r^3/3=32pi/3. Solve for r and get r=2. Then plug into the formula for finding the area of a circle A=r^2pi so you get 4pi.
It's A. 4 (m^2+9) (m+3) (m-3)