Answer:
I'm not sure for my answer but is B
I'm gonna put the steps
Step-by-step explanation:
x2−4x−12as(x+p)(x+q)
=−12apqs−12apsx−12aqsx−12asx2+x2−4x
Answer:
C=12
Step-by-step explanation:
2x12=24
3x12=36
5x12=60
Yes but it dose depend on the problem
It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (13)=3
- The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (24)=8
- The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.