Answer:
Step-by-step explanation:
38.
37.
Answer:
f(3) = 6
Step-by-step explanation:
Using the recursive rule and f(1) = 10 , then
f(2) = f(1) - 2 = 10 - 2 = 8
f(3) = f(2) - 2 = 8 - 2 = 6
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
Answer:
500,000 =
5 × 100,000
+ 0 × 10,000
+ 0 × 1,000
+ 0 × 100
+ 0 × 10
+ 0 × 1
Step-by-step explanation:
there are more then one ways of writing this so here's another example
500,000 =
500,000
+ 0
+ 0
+ 0
+ 0
+ 0
Answer:
the ratio would be 2:3 simplified
