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PIT_PIT [208]
3 years ago
15

The width of rectangle is the length minus 2 units. the area of the rectangle is 48 units. What is the width, units, of the rect

angle?
Mathematics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

6

Step-by-step explanation:

W=L-2

A=L*W

48=L(L-2)

48=L^2-2L

You factor and then you get L=8

W=8-2=6

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➷The best metric unit to use for the mass of a grasshopper is grams, because a grasshopper is very light and a gram is small.

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Calculate the surface area of the prism. Measurements are in centimetres
Nata [24]

Answer:

2804 cm²

Step-by-step explanation:

<u>Total area comprises of 6 faces: 2 trapezoids and 4 rectangles</u>

  • Trapezoid = 1/2*(14+32)*24 = 552 cm² each
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Factor completely, then place the answer in the proper location on the grid.
Tresset [83]
\mathrm{Factor\:out\:common\:term\:}9 \ \textgreater \  9\left(x^4-25y^8\right)

Factor \ \textgreater \  x^4-25y^8

\mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)
x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

x^2-5y^4 \ \textgreater \  \mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)
x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

9\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

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