Question

Using the law of sines, find the solutions for the missing inputs.

Answer 1

$\frac{a}{ \sin(a) } = \frac{b}{ \sin(b) }$
$\frac{12}{ \sin(38) } = \frac{b}{ \sin(85) }$
$\frac{12}{ \sin(38) } = \frac{a}{ \sin(57) }$
$180 - (85 + 38) = 57$
$\frac{12}{ \sin(38) } = \frac{b}{ \sin(85) }$
$\sin(85) \times \frac{12}{ \sin(38) } = b$
$\sin(57) \times \frac{12}{ \sin(38) } = a$
sorry for the order of steps