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iVinArrow [24]
3 years ago
10

I am really stuck for how to solve x with algebra it is so confusing does anyone have any tips

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
<span>Example: x − 2 = 4</span>

When we put 6 in place of x we get:

6 − 2 = 4

which is true

So x = 6 is a solution.

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Do not round your answer. Type in just the number. 0.48 is what % of 1 .6​
MakcuM [25]

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0.00768

Step-by-step explanation:

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Give an example of when and why one would use a continuity correction factor?
iris [78.8K]

Answer:

An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .

and continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution

Step-by-step explanation:

An example of when a continuity correction factor can be used is in finding the number of tails in 50 tosses of a coin within a given range .

continuity correction factor is used when a continuous probability distribution is used on a discrete probability distribution,  continuity correction factor creates an adjustment on a discrete distribution while using a continuous distribution

3 0
3 years ago
Angles of xyz are in the ratio 3:3:6. What are the measures of the angles
tankabanditka [31]
Let
x = 3a (first angle)
y = 3a (second angle)
z = 6a (third angle)

The total angle of a triangle is ALWAYS 180.
3a + 3a + 6a = 180
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a = 15

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4 0
3 years ago
The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w
LuckyWell [14K]

Answer: The required probability is \dfrac{4}{9}

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

2(\dfrac{8!}{3!\times 5!})

Total number of outcomes is given by

\dfrac{10!}{5!\times 5!}

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}

Hence, the required probability is \dfrac{4}{9}

3 0
3 years ago
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