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joja [24]
2 years ago
5

An Isosceles Triunde

Mathematics
2 answers:
Amanda [17]2 years ago
4 0

Answer:

base = x^4 - 3x^3+11x-4

Step-by-step explanation:

An isosceles triangle has 2 sides of equal length (a) and base (b)

⇒ perimeter of an isosceles = 2a + b

Given:

  • \textsf{leg (a)}=3x^4 - 6x-1  
  • \textsf{perimeter}=7x^4 - 3x^3-x-6

\implies \textsf{perimeter}=2a+b

\implies 7x^4 - 3x^3-x-6=2(3x^4 - 6x-1)+b

\implies 7x^4 - 3x^3-x-6=6x^4 - 12x-2+b

\implies x^4 - 3x^3+11x-4=b

Therefore, base = x^4 - 3x^3+11x-4

Mashcka [7]2 years ago
3 0

Answer:

Perimeter=sum of sides

  • Let base be y

\\ \tt\longmapsto 3x^4-6x-1+3x^4-6x-1+y=7x^4-3x^3-x-6

\\ \tt\longmapsto 6x^4-12x-2+y=7x^4-3x^3-x-6

\\ \tt\longmapsto y=x^4-3x^3+11x-4

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