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3 years ago

*****Write a polynomial using the roots -3,5i. PLEASE HELP IM SO LOST!!!

1 answer:

8 0

The polynomial $(x-a)$ has a unique root, $a$ , for any $a$ .

Hence $(x+3)(x-5i)$ is a polynomial with roots $-3$ and $5i$

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Question One:

Jobisdone [24]

Probability that 2 of the 10 chargers will be defective =0.35

Number of ways of selecting 10 chargers from 20 chargers is 20C10

20C10 = 184756

Number of ways of selecting 10 chargers from 20 = 184756

Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2

5C2 = 10

Since 2 defective chargers have been chosen, there remains 8 to choose

Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8

Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435

Probability that 2 of the 10 will be defective =

(10x6435)/184756

Probability that 2 of the 10 will be defective = 64350/184756

Probability that 2 of the 10 chargers will be defective =0.35

Learn more on probability here: brainly.com/question/24756209

8 0

3 years ago

Pls help i am on a timer

stich3 [128]

Answer:

$x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}$

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

$x^2 + (-1)^2 = 1 + (-1)^2$

$(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\$

⇒ take the square root of both sides;

$x-1 = +/- \ \ \sqrt{2} \\\\x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}$

Therefore, option B is the right solution.

3 0

3 years ago

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

N76 [4]

Answer:

7 feet

Step-by-step explanation:

Pythagorean theorem

sqrt(4.5^2 + 5.3^2) = hypotenuse

sqrt(48.34) = hypotenuse

6.95269732 = hypotenuse

round to nearest tenth

7 feet = the length of the hypotenuse

7 0

2 years ago

Read 2 more answers

Find the number of primes less than 190 using the principle of inclusion-exclusion.

Troyanec [42]

The number of primes less than 190 using the principle of inclusion-exclusion are 42

<h3>Principle of inclusion- exclusion</h3>

The principle of inclusion-exclusion is known as a counting technique that computes the number of elements satisfying at least one of several properties and guaranteeing that the numbers are not counted twice.

Prime numbers are numbers only divisible by 1 and itself.

Prime numbers less than 190 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181

They are 42 in number

Therefore, the number of primes less than 190 using the principle of inclusion-exclusion are 42

Learn more about prime numbers here:

brainly.com/question/874965

#SPJ11

8 0

2 years ago

Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. tan^2 B = 4

Anettt [7]

<u>ANSWER</u>

$B=63\degree$