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3 years ago

If the equation below is solved by graphing, which statement is true?

Mathematics

2 answers:

Soloha48 [4]3 years ago

8 0

Answer:

<h2>a. the curves intersect at approx. x=0.46</h2>

Step-by-step explanation:

The given function is

$log(6x+10)=log_{\frac{1}{2} }x$

If we graph this function, the result is like the image attached. There you can observe that the intersection point is at (0.464, 1.107).

If we round this points to the nearest hundred, they would be

x = 0.46 and y = 1.11.

Therefore, the right answer is

a. the curves intersect at approx. x=0.46

sergey [27]3 years ago

7 0

Step-by-step explanation:

the curves intersect at approcx=0.46

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Hard math question!

luda_lava [24]

First, let me show you some notation.

To show a matrix is an inverse of another matrix, we write $A^{-1}$

-1 is not an exponent. It just shows that a matrix is an inverse of another matrix.

For a 2x2 matrix, we can get the inverse by first making b and c negatives and swap the positions of a and d.

Then multiply each entry in the matrix by 1 divided by the determinant.

$\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]^{-1} = 
 \frac{1}{ad - bc}\left[\begin{array}{ccc}d&{-b}\\{-c}&a\end{array}\right] = \\ \\ \\ \left[\begin{array}{ccc}d(\frac{1}{ad-bc})&{-b}(\frac{1}{ad-bc}) \\ {-c}(\frac{1}{ad-bc}) &a(\frac{1}{ad-bc}) \end{array}\right]$

I hope this helped!

8 0

3 years ago

A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo

wel

The side lengths of the pool 10 ft and 45 ft.

SOLUTION:

Given, a rectangle swimming pool is 8 feet deep.

One side of the pool is 4.5 times longer than the other.

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,

$\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}$

On taking square root on both sides we get,

$\begin{array}{l}{\rightarrow\sqrt{n^{2}}=\sqrt{100}} \\\\ {\rightarrow n=10 \mathrm{ft}}\end{array}$

So, the width will be $4.5 n=4.5 \times 10=45 \mathrm{ft}$

5 0

3 years ago

Sylvia earns $7 per hour at her after school job. After working one week, she received a paycheck for $91.

makvit [3.9K]

Answer:

a.) $hours=13$

b.) $h\leq 15$

c.) $ $$105$

Step-by-step explanation:

a.) If she earns $7 'per' hour, this multiplication. After a week, we need to see how many hours she worked to earn $91, so this goes behind the equal sign. Let h be the unknown number of hours:

$7h=91$

Solve for h. Divide both sides by 7:

$\frac{7h}{7}=\frac{91}{7}\\\\h=13$

Sylvia worked 13 hours at a rate of $7 an hour.

b.) She can work at most 15 hours a week. At 'most' can also mean less than or equal to. Let h be hours:

$h\leq 15$

Sylvia can work less than or equal to 15 hours per week.

c.) If Sylvia can work 15 hours, plug in this value for h into an equation when she earns $7 per hour. Let the product of the hours and money equal t for total:

$t=7(15)\\t=105$