Question

The function f(x) is defined as, ormula1" title="f(x) = 3 + \frac{1}{2x-5}" alt="f(x) = 3 + \frac{1}{2x-5}" align="absmiddle" class="latex-formula">, x ≠ $\frac{5}{2}$
(a) Sketch the curve of f for -5 ≤ x ≤ 5, showing the asymptotes.

(b) Using your sketch, write down
(i) the equation of each asymptote;
(ii) the value of the x-intercept;
(iii) the value of the y-intercept.

Image attached.

Answer 1

Answer:

a) look at the figure

b) i) x = 2.5 , y = 3

   ii) x-intercept is 2.333

   iii) y-intercept is 2.8

Step-by-step explanation:

a) The points of the graph f(x) = 3+1/2x - 5 are:

f(-5) = 2.9333

f(-4) = 2.923

f(-3) = 2.909

f(-2) = 2.888

f(-1) = 2.857

f(0) = 2.8

f(1) = 2.666

f(2) = 2

f(3) = 4

f(4) = 3.333

f(5) = 3.2

b)

i) to find the vertical asymptotic put the denominator = 0

  2x - 5 = 0 ⇒ 2x = 5 ⇒ x = 5 ÷ 2 = 2.5

∴ The equation of the vertical asymptotic is x = 2.5

To find the horizontal asymptotic look at the degree of the numerator and denominator

∵ they are equal f(x) = (6x -14)/(2x - 5) ⇒ 6x ÷ 2x = 3

∴ The equation of the horizontal asymptotic is y = 3

ii) the value of x-intercept means put f(x) = 0

∴3 + 1/2x - 5 = 0 ⇒ 1/2x - 5 = -3 ⇒ -6x + 15 = 1 ⇒ 6x = 14

  x = 14/6 = 2.333

iii) The value of y-intercept means x = 0

∴ f(x) = 3 + 1/0 - 5 = 3 + (-0.2) = 2.8