Subtract 4 from both sides, solve using quadratic formula
ax^2+bx+c
(-b(+or-) Square Root of b^2 - 4ac)/2a
9x^2+9x-4=0
-9(+or-)Square root of 9^2-4(9)(-4)/2(9)
Solve^
Answer:
-1/3 < x <(or equal to) 2
Step-by-step explanation:
Firstly divide your inequality into two separate inequalities...
1) -1 < 6x + 1...then solve for the first one..,which then gives you....;
-2 < 6x....which gives us our first solution (x > -1/3)
Then the second inequality
2) 6x + 1 <(or equal to) 13
which then gives you....,
6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)
Then combine the two solutions into a compound solution
-1/3 < x <(or equal to) 2
Answer: 2x-3=15
2(9)-3=15
18-3=15
Answer:
Right Triangles and the Pythagorean Theorem
1.The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2 , can be used to find the length of any side of a right triangle.
2.The side opposite the right angle is called the hypotenuse (side c in the figure).
Isolate the x. Note the equal sign. What you do to one side, you do to the other.
First, add 9 to both sides
3/4x - 9 (+9) = 27 (+9)
3/4x = 36
Next, multiply 4/3 to both sides
(4/3)(3/4)x = 36(4/3)
x = 36(4/3)
Simplify.
x = 12(4)
x = 48
48 is your answer for x.
hope this helps
