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Jet001 [13]
3 years ago
11

What will be angle COD If: angle COD minus angle KOD equals 61degrees and angle COD minus angle KOC equals 53degrees?

Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0

Use algebra for such problems
let, Angle COD = x
Angle KOD = y
Angle KPC = z
Given ,. x - y = 61° ( Equation 1 )
x - z = 53° ( Equation 2 )
Subtract 1st equation from 2nd and you'll get :

z - y = 8° ( Equation 3 )
Now since , x + y + z = 180° ( Equation 4 )
Add Equation 3 to Equation 4 and you'll get
x + 2z = 188° ( Equation 5)
From Equation 2 we know that , x -z = 53°
or, x = 53° + z ( Equation 6 )
Put this value of 'x' in Equation 5 and solve for z. you'll get :
(53° + z) + 2z = 188°
or
3z = 188 - 53 = 135°
solving for z we get
z = 45°
put this value of z in Equation 5
x + ( 2 x 45° ) = 188°
or
x = 188° - 90° = 98°
hence , Angle COD = 98°














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I mark brainliest for all my questions that are answered right :) thx for helping me
allsm [11]
The correct answer is y= 0.513(1.833)^x


Explain


We will use the equation on this form

Y=ab^x

Let’s us plug in the coordinates of first point

(X, y) , ( 9, 120)

We will have

Y=ab^x

120= ab^9

Our equation for a will be

Ab^9 = 120

ab ^9 / b^9 = 120/ b^9


a = 120/ b^9

So will have


Y= 120/ b^9 • b^x

Then we will plug in coordinates for the second point


( x,y) = ( 10, 220)

We will have

Y= 120/b^9 • b^x

220 = 120/b^9 • b^10-9


220= 120b

Divide both side by 120

B= 11/6

B= 1.833333 = 1.833



Let’s plug in the value b=11/6 to our equation for a


A= 120/b^9

A= 120/ 11/6^9

A= 120/11^9/6^9


A=120 • 6^9 / 11^9

= 0.51285 which equal to 0.513



So therefore the answer is

Y= 0.513(1.833)^x


I hope this help you

:D
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Answer:

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Step-by-step explanation:

An antisymmetric relation () satisfies the following property:

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This means that if a|b and b|a then a = b

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b = bmn

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