Step-by-step explanation:
So I found the l.c.m which is 8 and I multiplied it by the numbers and then
The subtracted the both mixed numbers and I got an answer of 15/8
11111111111111117373646328299292922
B. and D. For the both I'm most likely sure
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>