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AVprozaik [17]
3 years ago
7

{6y^3+2y^2}{10y^2}= 10y 2 6y 3 +2y 2 ​ =start fraction, 6, y, cubed, plus, 2, y, squared, divided by, 10, y, squared, end fracti

on, equals Which values of yyy make the expression undefined?
Mathematics
1 answer:
malfutka [58]3 years ago
8 0

Answer:

y=0

Step-by-step explanation:

Definition:An expression is undefined at the value(s) at which the denominator equals zero.

We are to determine the value of y that makes the expression undefined.

\dfrac{6y^3+2y^2}{10y^2}

We equate the denominator to zero and solve for y.

10y^2=0\\y^2=0\\y=0

Therefore, at y=0, the given expression is undefined.

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Is either x=5 or x=3 a solution to 11- x <7
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Answer:

<h2><em><u>x = 5</u></em></h2>

Explanation:

11 - x < 7

  • 11 minus a number is less than 7

<em>Insert 5 into the equation</em>

11 - 5 < 7

<em>Simplify</em>

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<em>Insert 3 into the equation</em>

11 - 3 < 7

<em>Simplify</em>

8 < 7

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