If a sequence is defined recursively by (0)=3 and (n+1)=-f(n)+5 for n≥0, Then f(2) is equal to
1 answer:
Answer:
f(2) = 3
Step-by-step explanation:
We are given:
f(0) = 3
and
f(n+1) = -f(n) + 5
We have to find the value of f(2). In order to find f(2) we first have to find f(1)
f(n + 1) = - f(n) + 5
Using n = 0, we get:
f(0 + 1) = - f(0) + 5
f(1) = -f(0) + 5 Using the value of f(0), we get
f(1) = -3 + 5 = 2
Now using n = 1 in the function, we get:
f(1 + 1) = - f(1) + 5 Using the value of f(1), we get
f(2) = -2+ 5
f(2) = 3
Thus the value of f(2) will be 3
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