If a sequence is defined recursively by (0)=3 and (n+1)=-f(n)+5 for n≥0, Then f(2) is equal to

Mathematics

1 answer:

lana66690 [7]3 years ago

6 0

Answer:

f(2) = 3

Step-by-step explanation:

We are given:

f(0) = 3

and

f(n+1) = -f(n) + 5

We have to find the value of f(2). In order to find f(2) we first have to find f(1)

f(n + 1) = - f(n) + 5

Using n = 0, we get:

f(0 + 1) = - f(0) + 5

f(1) = -f(0) + 5 Using the value of f(0), we get

f(1) = -3 + 5 = 2

Now using n = 1 in the function, we get:

f(1 + 1) = - f(1) + 5 Using the value of f(1), we get

f(2) = -2+ 5

f(2) = 3

Thus the value of f(2) will be 3

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Answer:

2.4×10^6

Step-by-step explanation:

Put the numbers where the variables are and do the arithmetic. You can enter the numbers in scientific notation into your (scientific) calculator and have it show you the result in the same format.

r = (3.8×10^5)^2/(5.9×10^4) . . . . . denominator parentheses are required

Please note that in the above expression, parentheses are required around the denominator number. This is because it is a product of two numbers. In your pocket calculator or spreadsheet, you can enter that value as a single number (not a product). Parentheses are not required when you can do that.

r = (3.8²/5.9)×10^(5·2-4) ≈ 2.4×10^6

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The "exact" value is a repeating decimal with a long repeat. We have rounded to 2 significant digits here because the input numbers have that number of significant digits.