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ELEN [110]
3 years ago
14

Would this be 18?? Please help

Mathematics
1 answer:
Nikitich [7]3 years ago
7 0

Answer:

yes it would

Step-by-step explanation:

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PLEASE HELP ME QUICKKK, FIRST CORRECT PERSON GETS BRAINLIEST​
german

Answer:

The answer is Tennesse

Step-by-step explanation:

because it raises the prices by $45.50

8 0
2 years ago
Through [0, -7/5] and perpendicular to 3x-2y=6
Taya2010 [7]
Find a line going through the point
(0, -7/5) and perpendicular to the equation 3x - 2y = 6.

3x - 2y = 6

-2y = -3x + 6

y = (3/2)x - 3

The slope of the equation we seek must be the negative reciprocal of (3/2), which is -2/3.

So, m = -2/3

Use the point-slope formula. See the picture.

8 0
3 years ago
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
Find the arc length of the partial circle.
amid [387]

The arc length of the partial circle is 7.5π

<h3>Calculating arc length</h3>

From the question, we are to determine the arc length of the partial circle

The length of an arc can be calculated by using the formula

l = \frac{\theta}{360^\circ} \times 2\pi r

Where l is the length of the arc

\theta is the angle subtended

and r is the radius

From the diagram,

θ = 270°

r = 5

Putting the values into the equation, we get

l = \frac{270 ^\circ}{360^\circ} \times 2\pi \times 5

l = \frac{3}{4} \times 2\pi \times 5

l = \frac{30\pi}{4}

l = \frac{15}{2}\pi OR 7.5π

Hence, the arc length of the partial circle is 7.5π

Learn more on Calculating arc length here: brainly.com/question/16552139

#SPJ1

3 0
2 years ago
A line through (-4,6) with slope-3/2 and graph
marin [14]

Answer:

y = -\frac{3}{2}x

Step-by-step explanation:

Given

Passes through: (-4,6)

Slope: -3/2

Required

The equation and graph

The equation is calculated as:

y = m(x - x_1) + y_1

Where

m = -\frac{3}{2}

(x_1,y_1) = (-4,6)

So, we have:

y = -\frac{3}{2}(x --4) + 6

y = -\frac{3}{2}(x +4) + 6

Open bracket

y = -\frac{3}{2}x -6 + 6

y = -\frac{3}{2}x

See attachment for graph

7 0
3 years ago
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