Question

2. How much water could my well hold if the depth of the well is 30ft and the diameter of the well is 24ft?

Answer 1

Answer:

$V=4,320\pi\ ft^{3}$  or  $V=13,564.8\ ft^{3}$

Step-by-step explanation:

we know that

The volume of the cylinder (the well) is equal to

$V=\pi r^{2} h$

where

$r=24/2=12\ ft$ ----> the radius is half the diameter

$h=30\ ft$

substitute

$V=\pi (12)^{2}(30)$

$V=4,320\pi\ ft^{3}$

assume

$\pi =3.14$

$V=4,320(3.14)=13,564.8\ ft^{3}$

Answer 2

Answer:

$13,571.68\text{ ft}^3\approx 384307.18\text{ liters}$

Step-by-step explanation:

We are asked to find the amount of water that the well can hold.

We will use volume of cylinder formula to solve our given problem.

$V=\pi r^2 h$, where,

V = Volume of cylinder,

r = Radius,

h = Height.

$d=2r$

$24=2r$

$12=r$

$V=\pi (12\text{ ft})^2\times 30\text{ ft}$

$V=\pi*144 \text{ ft}^2\times 30\text{ ft}$

$V=4,320\pi \text{ ft}^3$

$V=13,571.68026\text{ ft}^3$

$V\approx 13,571.68\text{ ft}^3$

Since our given volume is in cubic feet, so we can convert it in liters by multiplying 13,571.68 by 28.3168.

$\text{Water in well}=13,571.68\text{ ft}^3\times\frac{28.3168\text{ liter}}{ \text{ ft}^3}$

$\text{Water in well}=384,307.180556\text{ liter}$

Therefore, the well could hold approximately 384307.18 liters of water.