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andreyandreev [35.5K]
3 years ago
10

What is 6y + 4 as an algebraic expression

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
IT IS ALREADY ONE AN ALGEBRAIC EXPRESSION!
notsponge [240]3 years ago
5 0
It already is one...
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rewona [7]
A bit blurry, but if I'm making it out correctly, that's

\displaystyle\int t\sqrt{(t^2-9)^3}\,\mathrm dt=\int t(t^2-9)^{3/2}\,\mathrm dt

Set u=t^2-9. Then \mathrm du=2t\,\mathrm dt, or t\,\mathrm dt=\dfrac{\mathrm du}2. The integral is then equivalent to

\displaystyle u^{3/2}\dfrac{\mathrm du}2=\frac12\int u^{3/2}\,\mathrm du
=\dfrac12\dfrac{u^{5/2}}{\frac52}+C
=\dfrac12\times\dfrac25u^{5/2}+C
=\dfrac15u^{5/2}+C
=\dfrac15(t^2-9)^{5/2}+C
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8 0
2 years ago
Please help me !! Ill difinately compensate you for your effort PLEASE!!! and if you don't know the answer then please be genero
Zina [86]

Answer:

When I squared the binomials, they became quadratic trinomials.

(Not sure if this is the kind of answer you want, sorry if it's not!)

(x-3)² = x² - 6x + 9

(x+2)² = x² + 4x + 4

(x-4)² = x² - 8x + 16

(x+5)² = x² + 10x + 25

3 0
3 years ago
Help me please? I don’t understand.
Mazyrski [523]
Use a protractor
It can’t help measure your lines
6 0
2 years ago
Read 2 more answers
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