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Delicious77 [7]
3 years ago
11

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Paul [167]3 years ago
8 0
The area of rectangle is lengthXwidth. A rectangular prism is essentially a rectangle with a height. So you multiply the area of rectangle with a height to get volume of prism.
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A rectangle has a perimeter of 30 inches.  Its length is one less than three times its width.  What are the length and width of
Alik [6]

Perimeter of a rectangle can be represented by 2* length + 2 * width

We can represent the width with the variable x

We can represent the length by the expression 3x-1


So, now we can make a forumla and solve

2(3x-1) + 2(x) = 30

6x-2+2x = 30

8x = 32

x = 4 is the width of the rectange.


Now we find the length

3(4)-1

11 = Length

4 0
3 years ago
Read 2 more answers
Shawn is conducting an experiment where he is flipping a fair coin (where the probability of the coin landing heads up is 50%).
Serhud [2]
I believe the answer is d
8 0
3 years ago
rajnish mother is 36 year old she is 6 year older than three times raju's age write an equation to find Raju age (take rajnish a
timofeeve [1]

Mother is 36  

and she is 6 year older than raju 3 times

N is rajiu age

N = 36÷ ( 6 x 3)

= 36 ÷ (18)

N = 2

Raju is 2 years old

<u></u>

4 0
3 years ago
The product of additive inverse and multiplicative inverse of -5 is ___
elena55 [62]

Answer:

-1

Step-by-step explanation:

the additive inverse of -5is5 because (-5+5=0) &

the multiplicative inverse of -5is 1/-5. because (-5*1/-5=1)

therefore 5*1/-5=5/1*1/-5

=5/-5

=-1

4 0
3 years ago
A woman wants to build a rectangular garden. She plans to use a side of a shed for one side of the garden. She has 84 yd of fenc
Ivan
Let x denote the length of the side of the garden which is covered fenced by a shed, and \frac{A}{x} be the width of the garden.

The perimeter of a rectangle is given by 2(length + width)
i.e. 2x + \frac{A}{x} = 84
which gives:
A = 84x - 2x^2

For the area to be maximum, the differentiation of A with respect to x must be equal to 0.
i.e. \frac{dA}{dx} =84-4x=0 \\ 4x=84 \\ x=21

Therefore, the maximum area of the garden enclosed is given by
84(21)-2(21)^2=1764-2(441)=1764-882=882 \, yd^2

3 0
3 years ago
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