Equation:
89.50=2.35c+5.50d
If theres 22 dogs and cats in total you can plug in number less than 22 for c(# of cats) and d(# of dogs).
So we try pats numbers 8 cats and 14 dogs so
89.50=2.35(8)+5.50(14)
89.50=18.8+77
89.50=95.8
So pats numbers were wrong so we try different numbers
So i started pluging in numbers from under 22 so i got c is 10 and d is 12 lets try it with the equation
89.50=2.35(10)+5.50(12)
89.50=23.5+66
89.50=89.50 so it works the answer to how many number of dogs and cats is 12 dogs and 10 cats
Answer:
use elimination
8x-3y=2
-8x-5y=46
8x cancel out
-5y-3y= -8y= 48
48/-8= -6y
Step-by-step explanation:
ANSWER= -6y
P(3,3)
left 1, up 4 then
P'(2, 7)
answer
c. (2,7)
Answer:
12:1
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