This is the answer
Uh it has to be 20 characters long for me to give you the pic so here
Answer:
d)
Step-by-step explanation:
it does not begin at 0,0
it is beginning at the 1
A 99% confidence interval for the population mean of high school students that take the bus to school every day is b) ci=(44.34%, 54.43%)
We need to find the 99% confidence interval for the population mean of high school students that take the bus to school everyday
A confidence interval is a range of estimates for an unknown parameter. The confidence interval is calculated at the specified confidence level; the most common is the 95% confidence level, but sometimes other levels are used, such as 90% or 99%.
The confidence interval of proportions is given by:
π ± z √(π (1-π) /n)
π is the sample proportion.
z is the critical value.
n is the sample size.
For 99% confidence interval the value of z is 2.58
π = 321/650
The confidence interval is given by
=321/650 ± 2.58 √( (321/650) × [ 1 - (321/650) ] ÷ 650)
= (0.493846 ± 0.050594)
=(0.4434 , 0.5443)
=(44.34 % , 54.43 %)
Hence a 99% confidence interval for the population mean of high school students that take the bus to school every day is ci=(44.34%, 54.43%)
<u>Learn more about confidence interval:</u>
brainly.com/question/28052710
# SPJ4
Answer:
-7
Step-by-step explanation:
Answer: The area of the mirror is 113.14 sq. inches [approx.].
Step-by-step explanation: Given that a circular can till 375 ft² of land in 15 min.
We are to find the area of the mirror in square inches.
The AREA of a circle with radius 'r' units is given by

The diameter of the circular mirror is 12 inches, so the radius of the mirror will be

Therefore, the area of the circular mirror is
![A=\pi r^2=\frac{22}{7}\times 6^2=\dfrac{22\times 36}{7}=113.14~\textup{sq inches}~\textup{[approx.]}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D%5Cfrac%7B22%7D%7B7%7D%5Ctimes%206%5E2%3D%5Cdfrac%7B22%5Ctimes%2036%7D%7B7%7D%3D113.14~%5Ctextup%7Bsq%20inches%7D~%5Ctextup%7B%5Bapprox.%5D%7D)
Thus, the area of the mirror is 113.14 sq. inches [approx.].